3.1.16 \(\int (1+\text {csch}^2(x))^{3/2} \, dx\) [16]

Optimal. Leaf size=29 \[ -\frac {1}{2} \coth ^2(x)^{3/2} \tanh (x)+\sqrt {\coth ^2(x)} \log (\sinh (x)) \tanh (x) \]

[Out]

-1/2*(coth(x)^2)^(3/2)*tanh(x)+ln(sinh(x))*(coth(x)^2)^(1/2)*tanh(x)

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Rubi [A]
time = 0.03, antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {4206, 3739, 3554, 3556} \begin {gather*} \tanh (x) \sqrt {\coth ^2(x)} \log (\sinh (x))-\frac {1}{2} \tanh (x) \coth ^2(x)^{3/2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 + Csch[x]^2)^(3/2),x]

[Out]

-1/2*((Coth[x]^2)^(3/2)*Tanh[x]) + Sqrt[Coth[x]^2]*Log[Sinh[x]]*Tanh[x]

Rule 3554

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[b*((b*Tan[c + d*x])^(n - 1)/(d*(n - 1))), x] - Dis
t[b^2, Int[(b*Tan[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1]

Rule 3556

Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-Log[RemoveContent[Cos[c + d*x], x]]/d, x] /; FreeQ[{c, d}, x]

Rule 3739

Int[(u_.)*((b_.)*tan[(e_.) + (f_.)*(x_)]^(n_))^(p_), x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x], x]}, Di
st[(b*ff^n)^IntPart[p]*((b*Tan[e + f*x]^n)^FracPart[p]/(Tan[e + f*x]/ff)^(n*FracPart[p])), Int[ActivateTrig[u]
*(Tan[e + f*x]/ff)^(n*p), x], x]] /; FreeQ[{b, e, f, n, p}, x] &&  !IntegerQ[p] && IntegerQ[n] && (EqQ[u, 1] |
| MatchQ[u, ((d_.)*(trig_)[e + f*x])^(m_.) /; FreeQ[{d, m}, x] && MemberQ[{sin, cos, tan, cot, sec, csc}, trig
]])

Rule 4206

Int[(u_.)*((a_) + (b_.)*sec[(e_.) + (f_.)*(x_)]^2)^(p_), x_Symbol] :> Int[ActivateTrig[u*(b*tan[e + f*x]^2)^p]
, x] /; FreeQ[{a, b, e, f, p}, x] && EqQ[a + b, 0]

Rubi steps

\begin {align*} \int \left (1+\text {csch}^2(x)\right )^{3/2} \, dx &=\int \coth ^2(x)^{3/2} \, dx\\ &=\left (\sqrt {\coth ^2(x)} \tanh (x)\right ) \int \coth ^3(x) \, dx\\ &=-\frac {1}{2} \coth ^2(x)^{3/2} \tanh (x)+\left (\sqrt {\coth ^2(x)} \tanh (x)\right ) \int \coth (x) \, dx\\ &=-\frac {1}{2} \coth ^2(x)^{3/2} \tanh (x)+\sqrt {\coth ^2(x)} \log (\sinh (x)) \tanh (x)\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 24, normalized size = 0.83 \begin {gather*} -\frac {1}{2} \sqrt {\coth ^2(x)} \left (\text {csch}^2(x)-2 \log (\sinh (x))\right ) \tanh (x) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 + Csch[x]^2)^(3/2),x]

[Out]

-1/2*(Sqrt[Coth[x]^2]*(Csch[x]^2 - 2*Log[Sinh[x]])*Tanh[x])

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(119\) vs. \(2(23)=46\).
time = 1.60, size = 120, normalized size = 4.14

method	result	size
risch	\(-\frac {\left ({\mathrm e}^{2 x}-1\right ) \sqrt {\frac {\left (1+{\mathrm e}^{2 x}\right )^{2}}{\left ({\mathrm e}^{2 x}-1\right )^{2}}}\, x}{1+{\mathrm e}^{2 x}}-\frac {2 \sqrt {\frac {\left (1+{\mathrm e}^{2 x}\right )^{2}}{\left ({\mathrm e}^{2 x}-1\right )^{2}}}\, {\mathrm e}^{2 x}}{\left (1+{\mathrm e}^{2 x}\right ) \left ({\mathrm e}^{2 x}-1\right )}+\frac {\left ({\mathrm e}^{2 x}-1\right ) \sqrt {\frac {\left (1+{\mathrm e}^{2 x}\right )^{2}}{\left ({\mathrm e}^{2 x}-1\right )^{2}}}\, \ln \left ({\mathrm e}^{2 x}-1\right )}{1+{\mathrm e}^{2 x}}\)	\(120\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1+csch(x)^2)^(3/2),x,method=_RETURNVERBOSE)

[Out]

-1/(1+exp(2*x))*(exp(2*x)-1)*((1+exp(2*x))^2/(exp(2*x)-1)^2)^(1/2)*x-2/(1+exp(2*x))/(exp(2*x)-1)*((1+exp(2*x))
^2/(exp(2*x)-1)^2)^(1/2)*exp(2*x)+1/(1+exp(2*x))*(exp(2*x)-1)*((1+exp(2*x))^2/(exp(2*x)-1)^2)^(1/2)*ln(exp(2*x
)-1)

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Maxima [A]
time = 0.50, size = 44, normalized size = 1.52 \begin {gather*} -x - \frac {2 \, e^{\left (-2 \, x\right )}}{2 \, e^{\left (-2 \, x\right )} - e^{\left (-4 \, x\right )} - 1} - \log \left (e^{\left (-x\right )} + 1\right ) - \log \left (e^{\left (-x\right )} - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+csch(x)^2)^(3/2),x, algorithm="maxima")

[Out]

-x - 2*e^(-2*x)/(2*e^(-2*x) - e^(-4*x) - 1) - log(e^(-x) + 1) - log(e^(-x) - 1)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 190 vs. \(2 (23) = 46\).
time = 0.40, size = 190, normalized size = 6.55 \begin {gather*} -\frac {x \cosh \left (x\right )^{4} + 4 \, x \cosh \left (x\right ) \sinh \left (x\right )^{3} + x \sinh \left (x\right )^{4} - 2 \, {\left (x - 1\right )} \cosh \left (x\right )^{2} + 2 \, {\left (3 \, x \cosh \left (x\right )^{2} - x + 1\right )} \sinh \left (x\right )^{2} - {\left (\cosh \left (x\right )^{4} + 4 \, \cosh \left (x\right ) \sinh \left (x\right )^{3} + \sinh \left (x\right )^{4} + 2 \, {\left (3 \, \cosh \left (x\right )^{2} - 1\right )} \sinh \left (x\right )^{2} - 2 \, \cosh \left (x\right )^{2} + 4 \, {\left (\cosh \left (x\right )^{3} - \cosh \left (x\right )\right )} \sinh \left (x\right ) + 1\right )} \log \left (\frac {2 \, \sinh \left (x\right )}{\cosh \left (x\right ) - \sinh \left (x\right )}\right ) + 4 \, {\left (x \cosh \left (x\right )^{3} - {\left (x - 1\right )} \cosh \left (x\right )\right )} \sinh \left (x\right ) + x}{\cosh \left (x\right )^{4} + 4 \, \cosh \left (x\right ) \sinh \left (x\right )^{3} + \sinh \left (x\right )^{4} + 2 \, {\left (3 \, \cosh \left (x\right )^{2} - 1\right )} \sinh \left (x\right )^{2} - 2 \, \cosh \left (x\right )^{2} + 4 \, {\left (\cosh \left (x\right )^{3} - \cosh \left (x\right )\right )} \sinh \left (x\right ) + 1} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+csch(x)^2)^(3/2),x, algorithm="fricas")

[Out]

-(x*cosh(x)^4 + 4*x*cosh(x)*sinh(x)^3 + x*sinh(x)^4 - 2*(x - 1)*cosh(x)^2 + 2*(3*x*cosh(x)^2 - x + 1)*sinh(x)^
2 - (cosh(x)^4 + 4*cosh(x)*sinh(x)^3 + sinh(x)^4 + 2*(3*cosh(x)^2 - 1)*sinh(x)^2 - 2*cosh(x)^2 + 4*(cosh(x)^3
- cosh(x))*sinh(x) + 1)*log(2*sinh(x)/(cosh(x) - sinh(x))) + 4*(x*cosh(x)^3 - (x - 1)*cosh(x))*sinh(x) + x)/(c
osh(x)^4 + 4*cosh(x)*sinh(x)^3 + sinh(x)^4 + 2*(3*cosh(x)^2 - 1)*sinh(x)^2 - 2*cosh(x)^2 + 4*(cosh(x)^3 - cosh
(x))*sinh(x) + 1)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (\operatorname {csch}^{2}{\left (x \right )} + 1\right )^{\frac {3}{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+csch(x)**2)**(3/2),x)

[Out]

Integral((csch(x)**2 + 1)**(3/2), x)

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 73 vs. \(2 (23) = 46\).
time = 0.40, size = 73, normalized size = 2.52 \begin {gather*} -x \mathrm {sgn}\left (e^{\left (4 \, x\right )} - 1\right ) + \log \left ({\left | e^{\left (2 \, x\right )} - 1 \right |}\right ) \mathrm {sgn}\left (e^{\left (4 \, x\right )} - 1\right ) - \frac {3 \, e^{\left (4 \, x\right )} \mathrm {sgn}\left (e^{\left (4 \, x\right )} - 1\right ) - 2 \, e^{\left (2 \, x\right )} \mathrm {sgn}\left (e^{\left (4 \, x\right )} - 1\right ) + 3 \, \mathrm {sgn}\left (e^{\left (4 \, x\right )} - 1\right )}{2 \, {\left (e^{\left (2 \, x\right )} - 1\right )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+csch(x)^2)^(3/2),x, algorithm="giac")

[Out]

-x*sgn(e^(4*x) - 1) + log(abs(e^(2*x) - 1))*sgn(e^(4*x) - 1) - 1/2*(3*e^(4*x)*sgn(e^(4*x) - 1) - 2*e^(2*x)*sgn
(e^(4*x) - 1) + 3*sgn(e^(4*x) - 1))/(e^(2*x) - 1)^2

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int {\left (\frac {1}{{\mathrm {sinh}\left (x\right )}^2}+1\right )}^{3/2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1/sinh(x)^2 + 1)^(3/2),x)

[Out]

int((1/sinh(x)^2 + 1)^(3/2), x)

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